MHT CET · Physics · Current Electricity
A potentiometer wire is \(4 \mathrm{~m}\) long and potential difference of \(3 \mathrm{~V}\) is maintained between the ends. The e.m.f. of the cell which balances against a length of \(100 \mathrm{~cm}\) of the potentiometer wire is
- A \(0.50\mathrm{V}\)
- B \(0.60 \mathrm{~V}\)
- C \(3.0 .75 \mathrm{~V}\)
- D \(4.0 .25 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(3.0 .75 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Potential gradient \(=\frac{3}{4} \frac{\mathrm{V}}{\mathrm{m}}\)
So, emf against \(100 \mathrm{~cm}=\frac{3}{4} \times 1 \mathrm{~V}=0.75 \mathrm{~V}\)
So, emf against \(100 \mathrm{~cm}=\frac{3}{4} \times 1 \mathrm{~V}=0.75 \mathrm{~V}\)
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