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MHT CET · Physics · Current Electricity

A potentiometer wire has length L for given cell of emf E, the balancing length is L3 from the positive end of the wire. If the length of potentiometer wire is increased by 50% , then for the same cell, the balance point is obtained at length

  1. A L2 from positive end
  2. B L5 from positive end
  3. C L3 from positive end
  4. D L4 from positive end
Verified Solution

Answer & Solution

Correct Answer

(A) L2 from positive end

Step-by-step Solution

Detailed explanation

For cell of emf E balancing length
=L3=13×L (length of wire)
Increased length of wire = L+L2=3L2
Since, the cell is the same, therefore the new balancing length
= 13 (new increased length)
=13×32L
=L2
Therefore, for the same cell the balance point will be as length L2 from positive end.
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