MHT CET · Physics · Waves and Sound
A pipe open at both ends of length \(1.5 \mathrm{~m}\) is dipped in water such that the second overtone of vibrating air column is resonating with a tuning fork of frequency \(330 \mathrm{~Hz}\). If speed of sound in air is \(330 \mathrm{~m} / \mathrm{s}\) then the length of the pipe immersed in water is (Neglect end correction)
- A \(0.35 \mathrm{~m}\)
- B \(0.25 \mathrm{~m}\)
- C \(0.55 \mathrm{~m}\)
- D \(0.45 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0.25 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Let the length of the pipe immersed in water is \(\ell\) Now it becomes closed pipe, then second overtone
\(
\begin{aligned}
& \frac{5 \mathrm{v}}{4(1.5-\ell)}=330 \\
& \ell=1.5-1.25=0.25 \mathrm{~m}
\end{aligned}
\)
\(
\begin{aligned}
& \frac{5 \mathrm{v}}{4(1.5-\ell)}=330 \\
& \ell=1.5-1.25=0.25 \mathrm{~m}
\end{aligned}
\)
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