MHT CET · Physics · Waves and Sound
A pipe open at both ends and a pipe closed at one end have save same length. The ratio of frequencies of air columns in their \(\mathrm{p}^{\text {th }}\) overtone respectively is
- A \(\frac{p}{2 p+1}\)
- B \(\frac{p+1}{2 p}\)
- C \(\frac{p+1}{2 p+1}\)
- D \(\frac{2(p+1)}{2 p+1}\)
Answer & Solution
Correct Answer
(D) \(\frac{2(p+1)}{2 p+1}\)
Step-by-step Solution
Detailed explanation
Let \(l\) be the length of the pipe and \(v\) the speed of the sound. The frequency of the open organ pipe of \(\mathrm{p}^{\text {th }}\) overtone is,
\(\mathrm{f}_0=(\mathrm{p}+1) \frac{\mathrm{v}}{21}\)
And frequency of closed organ pipe of nth overtone is,
\(\mathrm{f}_{\mathrm{c}}=(\mathrm{p}+2) \frac{\mathrm{v}}{41}\)
The desired ratio is thus,
\(\frac{\mathrm{f}_0}{\mathrm{f}_{\mathrm{c}}}=\frac{2(\mathrm{p}+1)}{2 \mathrm{p}+1}\)
\(\mathrm{f}_0=(\mathrm{p}+1) \frac{\mathrm{v}}{21}\)
And frequency of closed organ pipe of nth overtone is,
\(\mathrm{f}_{\mathrm{c}}=(\mathrm{p}+2) \frac{\mathrm{v}}{41}\)
The desired ratio is thus,
\(\frac{\mathrm{f}_0}{\mathrm{f}_{\mathrm{c}}}=\frac{2(\mathrm{p}+1)}{2 \mathrm{p}+1}\)
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