MHT CET · Physics · Waves and Sound
A pipe closed at one end has lengh \(0 \cdot 8 \mathrm{~cm}\). At its open end a \(0.5 \mathrm{~m}\) long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is \(50 \mathrm{~N}\) and the speed of sound is \(320 \mathrm{~m} / \mathrm{s}\), the mass of the string is
- A 8 gram
- B 2 gram
- C 10 gram
- D 4 gram
Answer & Solution
Correct Answer
(C) 10 gram
Step-by-step Solution
Detailed explanation
\(f_p = \frac{v_{sound}}{4L_p} = \frac{320}{4 \times 0.8} = 100 \mathrm{~Hz}\) \(f_s = \frac{n}{2L_s}\sqrt{\frac{T}{\mu}}\)
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