MHT CET · Physics · Mathematics in Physics
A physical quantity \(A\) can be determined by measuring parameters \(B\), \(C, D\) and \(E\) using the relation \(A=\frac{B^\alpha C^\beta}{D^\gamma E^\delta}\). If the maximum errors in the measurement are b %, c %, d % and e % then maximum error in the value of \(A\) is
- A \((\alpha \mathrm{b}+\beta \mathrm{c}-\gamma \mathrm{d}-\delta \mathrm{e}) \%\)
- B \((b+c-d-e) \%\)
- C \((\alpha \mathrm{b}+\beta \mathrm{c}+\gamma \mathrm{d}+\delta \mathrm{e}) \%\)
- D \((b+c+d+e) \%\)
Answer & Solution
Correct Answer
(C) \((\alpha \mathrm{b}+\beta \mathrm{c}+\gamma \mathrm{d}+\delta \mathrm{e}) \%\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta A}{A} \times 100\% = \left( |\alpha| \frac{\Delta B}{B} + |\beta| \frac{\Delta C}{C} + |-\gamma| \frac{\Delta D}{D} + |-\delta| \frac{\Delta E}{E} \right) \times 100\% = (\alpha \mathrm{b} + \beta \mathrm{c} + \gamma \mathrm{d} + \delta \mathrm{e}) \% \)
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