MHT CET · Physics · Dual Nature of Matter
A photon of wavelength 3315 Ã… falls on a photocathode and an electron of energy
\(3 \times 10^{-19} \mathrm{~J}\) is ejected. The threshold wavelength of photon is [Planck's constant (h)
\(=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\), velocity of light \(\left.(\mathrm{c})=3 \times 10^{8} \mathrm{~m} / \mathrm{s}\right]\)
- A \(6630 Å\)
- B \(3315 Å\)
- C \(5000 Å\)
- D \(1130 Å\)
Answer & Solution
Correct Answer
(A) \(6630 Å\)
Step-by-step Solution
Detailed explanation
\(\phi_{0}=\frac{h c}{\lambda}-E\)
\(=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{3315 \times 10^{-10}}-3 \times 10^{-19}=(6-3) \times\) \(10^{-19}=3 \times 10^{-19}\)
\(\lambda_{0}=\frac{\mathrm{hc}}{\phi_{0}}=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{3 \times 10^{-19}} \approx 6630 ~Å\)
\(=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{3315 \times 10^{-10}}-3 \times 10^{-19}=(6-3) \times\) \(10^{-19}=3 \times 10^{-19}\)
\(\lambda_{0}=\frac{\mathrm{hc}}{\phi_{0}}=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{3 \times 10^{-19}} \approx 6630 ~Å\)
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