MHT CET · Physics · Dual Nature of Matter
A photoelectric surface is illuminated successively by monochromatic light of Wavelength \(\lambda\) and \((\lambda / 3)\). If the maximum kinetic energy of the emitted photoelectrons in the second case is 4 times that in the first case, the work function of the surface of the material is ( \(\mathrm{h}=\) Planck's constant, \(\mathrm{c}=\) speed of light \()\)
- A \(\frac{\mathrm{hc}}{\lambda}\)
- B \(\frac{\mathrm{hc}}{2 \lambda}\)
- C \(\frac{\mathrm{hc}}{3 \lambda}\)
- D \(\frac{3 \mathrm{hc}}{\lambda}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{hc}}{3 \lambda}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \quad 1^{\text {st }} \text { case: } \\
& \mathrm{E}_0=\frac{\mathrm{hc}}{\lambda}-\phi...(i) \\
& 2^{\text {nd }} \text { case: } \\
& 4 \mathrm{E}_0=\frac{\mathrm{hc}}{\frac{\lambda}{3}}-\phi ...(ii)\\
& \therefore \quad \frac{4 \mathrm{E}_0}{\mathrm{E}_0}=\frac{\frac{3 \mathrm{hc}}{\lambda}-\phi}{\frac{\mathrm{hc}}{\lambda}-\phi} \\
& \frac{4 \mathrm{hc}}{\lambda}-4 \phi=\frac{3 \mathrm{hc}}{\lambda}-\phi \\
& \phi=\frac{\mathrm{hc}}{3 \lambda}
\end{aligned}\)
\(\ldots[\) From(i) and (ii) \(]\)
& \quad 1^{\text {st }} \text { case: } \\
& \mathrm{E}_0=\frac{\mathrm{hc}}{\lambda}-\phi...(i) \\
& 2^{\text {nd }} \text { case: } \\
& 4 \mathrm{E}_0=\frac{\mathrm{hc}}{\frac{\lambda}{3}}-\phi ...(ii)\\
& \therefore \quad \frac{4 \mathrm{E}_0}{\mathrm{E}_0}=\frac{\frac{3 \mathrm{hc}}{\lambda}-\phi}{\frac{\mathrm{hc}}{\lambda}-\phi} \\
& \frac{4 \mathrm{hc}}{\lambda}-4 \phi=\frac{3 \mathrm{hc}}{\lambda}-\phi \\
& \phi=\frac{\mathrm{hc}}{3 \lambda}
\end{aligned}\)
\(\ldots[\) From(i) and (ii) \(]\)
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