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MHT CET · Physics · Waves and Sound

A person standing between two parallel cliffs fires a gun and hears two echoes, first echo after 1 second and the second echo after 3 second. The distance between the two cliffs is (Velocity of sound \(=340 \mathrm{~m} / \mathrm{s}\) )

  1. A 340 m
  2. B 680 m
  3. C 1020 m
  4. D 1360 m
Verified Solution

Answer & Solution

Correct Answer

(B) 680 m

Step-by-step Solution

Detailed explanation

\(d_1 = \frac{v t_1}{2} = \frac{340 \mathrm{~m/s} \times 1 \mathrm{~s}}{2} = 170 \mathrm{~m}\) \(d_2 = \frac{v t_2}{2} = \frac{340 \mathrm{~m/s} \times 3 \mathrm{~s}}{2} = 510 \mathrm{~m}\)