MHT CET · Physics · Oscillations
A pendulum clock is running fast. To correct its time, we should
- A reduced the mass of bob
- B reduce the amplitude of oscillation
- C increase the length of pendulum
- D reduce the length of the pendulum
Answer & Solution
Correct Answer
(C) increase the length of pendulum
Step-by-step Solution
Detailed explanation
The periodic time of a pendulum is given by
\(
\begin{aligned}
& \mathrm{T}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}}} \\
& \therefore \mathrm{T} \propto \sqrt{\ell}
\end{aligned}
\)
Hence to increase the periodic time, length has to be increased. The periodic time is independent of mass and amplitude.
\(
\begin{aligned}
& \mathrm{T}=2 \pi \sqrt{\frac{\ell}{\mathrm{g}}} \\
& \therefore \mathrm{T} \propto \sqrt{\ell}
\end{aligned}
\)
Hence to increase the periodic time, length has to be increased. The periodic time is independent of mass and amplitude.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- If ' \(\Delta Q^{\prime}\) is the amount of heat supplied to 'n' moles of a diatonic gas at constant pressure, ' \(\triangle \mathrm{U}^{\prime}\) is the change in internal energy and ' \(\triangle \mathrm{W}^{\prime}\) is the work done, then \(\Delta \mathrm{W}: \Delta \mathrm{U}: \Delta \mathrm{Q}\) isMHT CET 2020 Medium
- A spring has a certain mass suspended from it and its period for vertical oscillations is ' \(T_1\) '. The spring is now cut in to two equal halves and the same mass is suspended from one of the halves. The period of vertical oscillations is now ' \(T_2\) '. The ratio \(T_1 / T_2\) isMHT CET 2023 Hard
- In an isobaric process of an ideal gas, the ratio of work done by the system to the heat supplied \(\left(\frac{W}{Q}\right)\) isMHT CET 2024 Easy
- The spectral series observed for hydrogen atom found in visible region isMHT CET 2024 Easy
- The voltmeter has range 10 V and its internal resistance is \(50 \Omega\). To increase the range of voltmeter to 15 V , the resistance which is to be connected isMHT CET 2025 Medium
- Two current carrying identical coils are kept as shown in figure. The magnetic field at centre ' \(O\) ' is ( \(N\) and \(R\) represent the number of turns and radius of each coil respectively, \(\mu_0=\) permeability of free space)
MHT CET 2025 Medium
More PYQs from MHT CET
- \(\int \sin \sqrt{x} \mathrm{~d} x=\ldots+C\)
(where \(C\) is a constant of integration.)MHT CET 2022 Hard - A steel ring of radius 'r' is to be fitted over a wooden disc of radius 'R' \((\mathrm{R}>\mathrm{r})\). The force required to expand the ring so that it fits over the disc is \([\mathrm{Y}=\) Young's modulus of steel, \(\mathrm{A}=\) area of cross section of wire \(]\)MHT CET 2020 Hard
- If \(\mathrm{f}(\mathrm{x})=\frac{\mathrm{x}}{2}-1\), then on the interval \([0, \pi]\) where [.] represents greatest integer functionMHT CET 2022 Medium
- respectively. If they are coated with a material of same emissivity, rate of radiation of \({ }^{\prime} \mathrm{S}_{1}{ }^{\prime}\) is \(\mathrm{E}\) then rate of radiation of \(\mathrm{S}_{2}{ }^{\prime}\) is (spheres are of the same material)MHT CET 2020 Medium
- A particle moves according to the law \(s=t^{3}-6 t^{2}+9 t+25 .\) The displacement ofMHT CET 2020 Easy
- Heat of combustion of methane is \(-800 \mathrm{~kJ}\). What is the heat of combustion for \(4 \times 10^{-4} \mathrm{~kg}\) of methane?MHT CET 2009 Medium