MHT CET · Physics · Motion In Two Dimensions
A particle performing U.C.M. of radius \(\frac{\pi}{2} \mathrm{~m}\) makes ' \(\mathrm{x}\) ' revolutions in time ' \(\mathrm{t}^{\prime}\). Its tangential velocity is
- A \(\frac{\pi t}{x^{2}}\)
- B \(\frac{\pi \mathrm{x}^{2}}{\mathrm{t}}\)
- C \(\frac{\pi \mathrm{X}}{\mathrm{t}^{2}}\)
- D \(\frac{\pi^{2} x}{t}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi^{2} x}{t}\)
Step-by-step Solution
Detailed explanation
frequency \(f=\frac{x}{t}, \omega=2 \pi f=\frac{2 \pi x}{t}\) tangential velocity
\(V=\omega r=\frac{2 \pi x}{t} \cdot \frac{\pi}{2}=\frac{\pi^{2} x}{t}=3\)
\(V=\omega r=\frac{2 \pi x}{t} \cdot \frac{\pi}{2}=\frac{\pi^{2} x}{t}=3\)
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