MHT CET · Physics · Rotational Motion
A particle of mass \(m\) is rotating in a plane in circularpath of radius \(r\). Its angular momentum is \(L\). The centripetal force acting on the particle is
- A \(\frac{L^{2}}{m r}\)
- B \(\frac{L^{2} m}{r}\)
- C \(\frac{L^{2}}{m^{2} r^{2}}\)
- D \(\frac{L^{2}}{m r^{3}}\)
Answer & Solution
Correct Answer
(D) \(\frac{L^{2}}{m r^{3}}\)
Step-by-step Solution
Detailed explanation
Centripetal force, \(F=\frac{m v^{2}}{r}=\frac{m}{r} \frac{L^{2}}{m^{2} r^{2}}=\frac{L^{2}}{m r^{3}}\)
\(\left[\right.\) As \(\left.L=m v r \therefore v=\frac{L}{m r}\right]\)
\(\left[\right.\) As \(\left.L=m v r \therefore v=\frac{L}{m r}\right]\)
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