MHT CET · Physics · Rotational Motion
A particle of mass ' \(\mathrm{m}\) ' is rotating along a circular path of radius ' \(r\) ' having angular momentum ' \(L\) '. The centripetal force acting on the particle is given by
- A \(\frac{\mathrm{L}^2}{\mathrm{mr}}\)
- B \(\frac{\mathrm{L}^2}{\mathrm{mr}^2}\)
- C \(\frac{\mathrm{mL}^2}{\mathrm{r}}\)
- D \(\frac{\mathrm{L}^2}{\mathrm{mr}^3}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{L}^2}{\mathrm{mr}^3}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \text { Centripetal force }=m \omega^2 r \\ \therefore \quad & \omega=\frac{L}{I}=\frac{L}{m r^2} \quad \ldots(\because L=I \omega) \\ \therefore \quad & F=m\left(\frac{L}{m r^2}\right)^2 \quad r=\frac{m^2 r}{m^2 r^4}=\frac{L^2}{m r^3}\end{array}\)
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