MHT CET · Physics · Gravitation
A particle of mass ' \(\mathrm{m}\) ' is kept at rest a height \(3 \mathrm{R}\) from the surface of earth, where ' \(R\) ' is radius of earth and ' \(M\) ' is the mass of earth. The minimum speed with which it should be projected upward, so that it does not return back is ( \(\mathrm{g}=\) acceleration due to gravity on the earth's surface)
- A \(\left[\frac{\mathrm{GM}}{2 \mathrm{R}}\right]^{1 / 2}\)
- B \(\left[\frac{\mathrm{gR}}{4}\right]^{1 / 2}\)
- C \(\left[\frac{2 g}{R}\right]^{1 / 2}\)
- D \(\left[\frac{\mathrm{GM}}{\mathrm{R}}\right]^{1 / 2}\)
Answer & Solution
Correct Answer
(A) \(\left[\frac{\mathrm{GM}}{2 \mathrm{R}}\right]^{1 / 2}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{K}_{\mathrm{i}}+\mathrm{U}_{\mathrm{i}}=\mathrm{K}_{\mathrm{f}}+\mathrm{U}_{\mathrm{f}}\)
\(\frac{1}{2} \mathrm{mv}^2-\frac{\mathrm{GMm}}{4 \mathrm{R}}=0\)
\(\therefore \mathrm{v}=\left[\frac{\mathrm{GM}}{2 \mathrm{R}}\right]^{1 / 2}\)
\(\frac{1}{2} \mathrm{mv}^2-\frac{\mathrm{GMm}}{4 \mathrm{R}}=0\)
\(\therefore \mathrm{v}=\left[\frac{\mathrm{GM}}{2 \mathrm{R}}\right]^{1 / 2}\)
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