MHT CET · Physics · Magnetic Effects of Current
A particle of charge \(q\) moves with a velocity \(\vec{V}=\) ai in a magnetic field \(\overrightarrow{\mathrm{B}}=\mathrm{b} \hat{\mathrm{j}}+\mathrm{ck}\), where ' a ', ' b ' and ' c ' are constants. The magnitude of force experienced by particle is
- A \(q a \sqrt{b^2+c^2}\)
- B \(q a(b+c)\)
- C \(q a \sqrt{b^2-c^2}\)
- D zero
Answer & Solution
Correct Answer
(A) \(q a \sqrt{b^2+c^2}\)
Step-by-step Solution
Detailed explanation
\(\vec{F} = q(\vec{V} \times \vec{B})\) \(\vec{V} \times \vec{B} = (\text{ai}) \times (\text{b}\hat{\text{j}} + \text{c}\hat{\text{k}}) = \text{ab}(\hat{\text{i}} \times \hat{\text{j}}) + \text{ac}(\hat{\text{i}} \times \hat{\text{k}})\)
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