MHT CET · Physics · Rotational Motion
A particle moves along a circular path of radius \(r\) with uniform speed \(v\). The angle described by a particle in one second is
- A \(v r^2\)
- B \(\frac{v^2}{r}\)
- C \(\frac{r}{v}\)
- D \(\frac{v}{r}\)
Answer & Solution
Correct Answer
(D) \(\frac{v}{r}\)
Step-by-step Solution
Detailed explanation
Here, a particle moves along a circular path of radius \(r\) with uniform speed \(v\).
Thus, the angular velocity is:
\(\omega=\frac{v}{r}\)
The angle described by the radius vector is:
\(\theta=\omega t\)
For \(t=1 \mathrm{~s}\),
\(\theta=\omega=\frac{v}{r}\)
Thus, the angular velocity is:
\(\omega=\frac{v}{r}\)
The angle described by the radius vector is:
\(\theta=\omega t\)
For \(t=1 \mathrm{~s}\),
\(\theta=\omega=\frac{v}{r}\)
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