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MHT CET · Physics · Oscillations

A particle is performing S.H.M. about its mean position with an amplitude 'a' and periodic time ' T '. The speed of the particle when. its displacement from mean position' is \(\frac{\mathrm{a}}{3}\) will be

  1. A \(\frac{2 \pi \mathrm{a}}{\mathrm{T}}\)
  2. B \(\frac{4 \sqrt{2} \pi \mathrm{a}}{3 \mathrm{~T}}\)
  3. C \(\frac{4 \pi^2 a}{3 T}\)
  4. D \(\frac{\sqrt{3} \pi^2 a}{2 T}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{4 \sqrt{2} \pi \mathrm{a}}{3 \mathrm{~T}}\)

Step-by-step Solution

Detailed explanation

The speed of a particle performing SHM at displacement ' \(x\) ' from the mean position is given by, \(V=\omega \sqrt{a^2-x^2}\)
\(\begin{aligned}
& V=\omega \sqrt{a^2-\left(\frac{a}{3}\right)^2} \\
& V=\omega \sqrt{\frac{8 a^2}{9}} \\
& V=\frac{2 \pi}{T} \times \frac{2 \sqrt{2}}{3} \times a \\
& V=\frac{4 \sqrt{2} \pi a}{3 T}
\end{aligned}\)
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