MHT CET · Physics · Motion In Two Dimensions
A particle is performing a uniform circular motion along a circular of radius ' \(\mathrm{R}\) '. In half the period of revolution, its displacement and distance covered are respectively
- A \(2 R, \pi R\)
- B \(R, \pi R\)
- C \(2 \mathrm{R}, 2 \pi \mathrm{R}\)
- D \(\sqrt{2 R}, 2 \pi R\)
Answer & Solution
Correct Answer
(A) \(2 R, \pi R\)
Step-by-step Solution
Detailed explanation
In half the period, particle is diametrically opposite to its initial position. Hence, its displacement is \(2 \mathrm{R}\). It has covered a semicircle, hence distance covered by particle is \(\pi \mathrm{R}\).
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