MHT CET · Physics · Motion In Two Dimensions
A particle is moving in U.C.M. with speed \(V\) and radius \(R\). The angular acceleration of the particle is
- A \(\frac{V^2}{R}\) Perpendicular to the plane of the circle.
- B \(\frac{V^2}{R}\) along the tangent to the circle.
- C \(\frac{V^2}{R}\) along the radius towards the centre of the circle.
- D zero.
Answer & Solution
Correct Answer
(D) zero.
Step-by-step Solution
Detailed explanation
Concept-based.
During uniform circular motion, the angular velocity is fixed therefore, the angular acceleration is zero.
During uniform circular motion, the angular velocity is fixed therefore, the angular acceleration is zero.
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