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MHT CET · Physics · Motion In Two Dimensions

A particle is moving in a circle with uniform speed ' \(v\) '. In moving from a point to another diametrically opposite point

  1. A the momentum changes by \(\mathrm{mv}\)
  2. B the momentum changes by \(2 \mathrm{mv}\)
  3. C the kinetic energy changes by \(\frac{1}{2} \mathrm{mv}^2\)
  4. D the kinetic energy changes by \(\mathrm{mv}^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) the momentum changes by \(2 \mathrm{mv}\)

Step-by-step Solution

Detailed explanation


At both points, the momentum will be mv, but will be in opposite directions.
\(\begin{array}{ll}\therefore & \Delta \mathrm{P}=\mathrm{mv}-(-\mathrm{mv}) \\\therefore & \Delta \mathrm{P}=2 \mathrm{mv}
\end{array}\)
The momentum changes by \(2 \mathrm{mv}\).