MHT CET · Physics · Motion In Two Dimensions
A particle is moving in a circle with uniform speed ' \(v\) '. In moving from a point to another diametrically opposite point
- A the momentum changes by \(\mathrm{mv}\)
- B the momentum changes by \(2 \mathrm{mv}\)
- C the kinetic energy changes by \(\frac{1}{2} \mathrm{mv}^2\)
- D the kinetic energy changes by \(\mathrm{mv}^2\)
Answer & Solution
Correct Answer
(B) the momentum changes by \(2 \mathrm{mv}\)
Step-by-step Solution
Detailed explanation

At both points, the momentum will be mv, but will be in opposite directions.
\(\begin{array}{ll}\therefore & \Delta \mathrm{P}=\mathrm{mv}-(-\mathrm{mv}) \\\therefore & \Delta \mathrm{P}=2 \mathrm{mv}
\end{array}\)
The momentum changes by \(2 \mathrm{mv}\).
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