MHT CET · Physics · Motion In Two Dimensions
A particle is moving in a circle of radius 'R' with constant speed 'V'. The magnitude of average acceleration after half revolution is
- A \(\frac{2 V^{2}}{\pi R}\)
- B \(\frac{2 \pi}{R V^{2}}\)
- C \(\frac{2 \mathrm{~V}}{\pi \mathrm{R}^{2}}\)
- D \(\frac{2 R}{\pi V}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 V^{2}}{\pi R}\)
Step-by-step Solution
Detailed explanation
Change in speed after half revolution is \(2 \mathrm{~V}\)
\(\text {Time taken}=\frac{\pi R}{V}\)
\(\therefore \text {average speed}=\frac{2 V^{2}}{\pi R}\)
\(\text {Time taken}=\frac{\pi R}{V}\)
\(\therefore \text {average speed}=\frac{2 V^{2}}{\pi R}\)
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