MHT CET · Physics · Oscillations
A particle executes linear S.H.M. with amplitude 4 cm . The magnitude of velocity and acceleration is equal when it is at 3 cm from mean position. Time period of oscillation is
- A \(\frac{\pi}{\sqrt{7}}\)
- B \(\frac{6 \pi}{\sqrt{7}}\)
- C \(\frac{3 \pi}{\sqrt{7}}\)
- D \(\frac{5 \pi}{\sqrt{7}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi}{\sqrt{7}}\)
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