MHT CET · Physics · Laws of Motion
A particle describes a horizontal circle on smooth inner surface of a cone as shown in figure. If the height of the circle above the vertex is 10 cm . The speed of the particle is
(g, acceleration due to gravity \(=10 \mathrm{~m} / \mathrm{s}^2\) )

- A \(2 \mathrm{~m} / \mathrm{s}\)
- B \(1.5 \mathrm{~m} / \mathrm{s}\)
- C \(1 \mathrm{~m} / \mathrm{s}\)
- D \(0.5 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(C) \(1 \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(v = \sqrt{gh}\) \(v = \sqrt{(10)(0.1)}\)
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