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MHT CET · Physics · Current Electricity

A parallel plate condenser with oil (dielectric constant 2 ) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes

  1. A \(\sqrt{2 C}\)
  2. B \(2 C\)
  3. C \(\frac{C}{\sqrt{2}}\)
  4. D \(\frac{C}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{C}{2}\)

Step-by-step Solution

Detailed explanation

The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is.
\(C=\frac{K \varepsilon_{0} A}{d}\)
where \(\varepsilon_{0}=\) electric permittivity of free space \(K=\) dielectric constant \(A=\) area of each plate of capacitor \(d=\) distance between two plates When dielectric (oil) is removed, so capacitance
\(C_{0}=\frac{\varepsilon_{0} A}{d}\)
Comparing Eqs. (i) and (ii), we get
\(C=K C_{0}\)
\((\because K=2)\)