MHT CET · Physics · Electromagnetic Waves
A parallel plate capacitor with plate area \(A\) and plate separation \(d\) is charged by constant current I. A plane surface of area \(\mathrm{A} / 2\), parallel to the plates is drawn simultaneously between the plates. The displacement current through this area is
- A I
- B \(\frac{\mathrm{I}}{2}\)
- C \(\frac{\mathrm{I}}{4}\)
- D \(\frac{\mathrm{I}}{8}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{I}}{2}\)
Step-by-step Solution
Detailed explanation
Total displacement current through area \(A\) is \(I_{total} = I\). Displacement current density \(J_d = \frac{I_{total}}{A} = \frac{I}{A}\).
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