MHT CET · Physics · Alternating Current
A parallel plate capacitor having plates of radius \(6 \mathrm{~cm}\) has capacitance \(100 \mathrm{pF}\). It is connected to \(230 \mathrm{~V}\) a.c. supply with angular frequency \(300 \mathrm{rad} / \mathrm{s}\). the r.m.s. value of current is
- A \(6.9 \times 10^{-6} \mathrm{~A}\)
- B \(2.3 \times 10^{-5} \mathrm{~A}\)
- C \(6.9 \times 10^{-5} \mathrm{~A}\)
- D \(6.9 \times 10^{-7} \mathrm{~A}\)
Answer & Solution
Correct Answer
(A) \(6.9 \times 10^{-6} \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{i}=\frac{\mathrm{V}}{\mathrm{X}_{\mathrm{C}}}=\mathrm{V} \omega \mathrm{C} \\ & =230 \times 300 \times 100 \times 10^{-12} Å \\ & =6.9 \times 10^{-6} Å\end{aligned}\)
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