MHT CET · Physics · Capacitance
A parallel plate capacitor having plate area 'A' and separation 'd' is charged to a potential difference ' \(V\) '. The charging battery is disconnected and the plates are pulled apart to four times the initial separation. The work required to increase the distance between the plates is ( \(\epsilon_0=\) permittivity of free space)
- A \(\frac{\epsilon_0 \mathrm{AV}^2}{3 \mathrm{~d}}\)
- B \(\frac{\epsilon_0 \mathrm{AV}^2}{4 \mathrm{~d}}\)
- C \(\frac{2 \in_0 A V^2}{d}\)
- D \(\frac{3 \epsilon_0 A V^2}{2 d}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 \epsilon_0 A V^2}{2 d}\)
Step-by-step Solution
Detailed explanation
\(U_i = \frac{1}{2} C_i V^2 = \frac{1}{2} \left(\frac{\epsilon_0 A}{d}\right) V^2 = \frac{\epsilon_0 A V^2}{2d}\) \(Q = C_i V = \frac{\epsilon_0 A V}{d}\)
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