MHT CET · Physics · Capacitance
A parallel plate capacitor has uniform electric field 'E' in the space between the
plates. If the distance between plates is 'd' and area of each plate is 'A', the energy
stored in the capacitor is \(\left(\epsilon_{0}=\right.\) permittivity of free space \()\)
- A \(\frac{1}{2} \frac{\epsilon_{0} \mathrm{EA}}{\mathrm{d}}\)
- B \(\frac{1}{2} \epsilon_{0} \mathrm{E}^{2} \mathrm{Ad}\)
- C \(\frac{1}{2} \frac{\epsilon_{0} \mathrm{Ad}}{\mathrm{E}^{2}}\)
- D \(\frac{1}{2} \frac{\epsilon_{0} \mathrm{E}^{2} \mathrm{~A}}{\mathrm{~d}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2} \epsilon_{0} \mathrm{E}^{2} \mathrm{Ad}\)
Step-by-step Solution
Detailed explanation
Total energy \(=\) energy density volume
\(=\left(\frac{1}{2} \epsilon_{0} \mathrm{E}^{2}\right)(\mathrm{Ad})\)
\(=\left(\frac{1}{2} \epsilon_{0} \mathrm{E}^{2}\right)(\mathrm{Ad})\)
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