MHT CET · Physics · Capacitance
A parallel plate capacitor filled with oil of a dielectric constant 3 between the plates has capacitance ' \(C\) '. If the oil is removed, then the capacitance of the capacitor will be
- A \(\frac{\mathrm{C}}{\sqrt{3}}\)
- B \(3 \mathrm{C}\)
- C \(\sqrt{3} \mathrm{C}\)
- D \(\frac{C}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{C}{3}\)
Step-by-step Solution
Detailed explanation
\(
\mathrm{C}=\frac{\mathrm{K} \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{3 \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}
\)
After removing the oil, capacitance becomes
\(
\mathrm{C}^{\prime}=\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{\mathrm{C}}{3}
\)
\mathrm{C}=\frac{\mathrm{K} \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{3 \varepsilon_0 \mathrm{~A}}{\mathrm{~d}}
\)
After removing the oil, capacitance becomes
\(
\mathrm{C}^{\prime}=\frac{\varepsilon_0 \mathrm{~A}}{\mathrm{~d}}=\frac{\mathrm{C}}{3}
\)
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