MHT CET · Physics · Capacitance
A parallel plate air capacitor has capacitance \(C_p\). It is equally filled with parallel layers of materials of dielectric constants \(\mathrm{K}_1\) and \(\mathrm{K}_2\). Now its capacity becomes \(C_K\). The ratio \(C_P\) to \(C_K\) is
- A \(\mathrm{K}_1+\mathrm{K}_2\)
- B \(\frac{\mathrm{K}_1+\mathrm{K}_2}{\mathrm{~K}_1 \mathrm{~K}_2}\)
- C \(\frac{K_1+K_2}{2 K_1 K_2}\)
- D \(\frac{2 \mathrm{~K}_1 \mathrm{~K}_2}{\mathrm{~K}_1+\mathrm{K}_2}\)
Answer & Solution
Correct Answer
(C) \(\frac{K_1+K_2}{2 K_1 K_2}\)
Step-by-step Solution
Detailed explanation
\(C_p = \frac{\epsilon_0 A}{d}\) \(\frac{1}{C_K} = \frac{d/2}{K_1 \epsilon_0 A} + \frac{d/2}{K_2 \epsilon_0 A}\)
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