MHT CET · Physics · Capacitance
A parallel plate air capacitor has a uniform electric field \(E\) in the space between the plates. Area of each plate is \(A\) and the distance between the plates is \(d\). The energy stored in the capacitor is \(\left[\varepsilon_0=\right.\) permittivity of free space \(]\)
- A \(2 \varepsilon_0 E A d\)
- B \(\frac{\varepsilon_0 E^2}{2 A d}\)
- C \(\frac{1}{2} \varepsilon_0 E^2 A d\)
- D \(\frac{E^2 A d}{2 \varepsilon_0}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2} \varepsilon_0 E^2 A d\)
Step-by-step Solution
Detailed explanation
The energy stored in the capacitor is
\(U=\frac{1}{2} C V^2=\frac{1}{2}\left(\frac{\varepsilon_0 A}{d}\right)(E d)^2\)
\(U=\frac{1}{2} C V^2=\frac{1}{2}\left(\frac{\varepsilon_0 A}{d}\right)(E d)^2\)
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