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MHT CET · Physics · Nuclear Physics

A nucleus breaks into two nuclear parts, which have their velocity ratio \(2: 1\). The ratio of their nuclear radii will be

  1. A \(\sqrt{2}\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{2^{1 / 3}}\)
  4. D \(\frac{1}{\sqrt{2}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2^{1 / 3}}\)

Step-by-step Solution

Detailed explanation

By law of conservation of momentum, the two parts will have equal and opposite momentum, assuming the nucleus was initially at rest.
\(
\begin{aligned}
& \therefore \mathrm{m}_1 \mathrm{v}_1=\mathrm{m}_2 \mathrm{v}_2 \text { or } \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\frac{\mathrm{v}_2}{\mathrm{v}_1}=\frac{1}{2} \\
& \frac{\mathrm{m}_1}{\mathrm{~m}_2}=\left(\frac{\mathrm{r}_1}{\mathrm{r}_2}\right)^3=\frac{1}{2} \\
& \therefore \frac{\mathrm{r}_1}{\mathrm{r}_2}=\frac{1}{2^{1 / 3}}
\end{aligned}
\)