MHT CET · Physics · Mechanical Properties of Fluids
A needle is \(7 \mathrm{~cm}\) long. Assuming that the needle is not wetted by water, what is the weight of the needle, so that floats on water?
\(\left[\mathrm{T}=\text { surface tension of water }=70 \frac{\mathrm{dyne}}{\mathrm{cm}}\right]\) [acceleration due to gravity \(=980 \mathrm{~cm} \mathrm{~s}^{-2}\) ]
- A 1 g wt
- B 5 g wt
- C 3 g wt
- D 7 g wt
Answer & Solution
Correct Answer
(A) 1 g wt
Step-by-step Solution
Detailed explanation
The weight of the needle is balanced by the force due to surface tension
\(
\begin{aligned}
& \mathrm{W}=2 \mathrm{TL} \\
& =2 \times 70 \times 7 \\
& =980 \mathrm{dyne} \\
& =1 \mathrm{~g} \mathrm{wt}
\end{aligned}
\)
\(
\begin{aligned}
& \mathrm{W}=2 \mathrm{TL} \\
& =2 \times 70 \times 7 \\
& =980 \mathrm{dyne} \\
& =1 \mathrm{~g} \mathrm{wt}
\end{aligned}
\)
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