MHT CET · Physics · Center of Mass Momentum and Collision
A molecule of mass ' \(m\) ' moving with velocity ' \(\mathrm{v}\) ' makes 5 elastic collisions with a wall of container per second. The change in momentum of the wall per second in 5 collisions will be
- A \(10 \mathrm{mv}\)
- B \(5 \mathrm{mv}\)
- C \(\frac{1}{5} \mathrm{mv}\)
- D \(\frac{1}{10} \mathrm{mv}\)
Answer & Solution
Correct Answer
(A) \(10 \mathrm{mv}\)
Step-by-step Solution
Detailed explanation
Change in momentum in each collision is \([\mathrm{mv}-(-\mathrm{mv})]=2 \mathrm{mv}\) Hence change in momentum in 5 collisions is \(5 \times 2 \mathrm{mv}=10 \mathrm{mv}\)
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