MHT CET · Physics · Rotational Motion
A molecule consists of two atoms each of mass ' \(\mathrm{m}^{\prime}\) and separated by a distance ' \(\mathrm{d}^{\prime}\). At room temperature the average rotational kinetic energy is 'E', then its angular frequency is
- A \(\frac{2}{d} \sqrt{\frac{E}{m}}\)
- B \(\sqrt{\frac{m}{E d}}\)
- C \(\frac{d}{2} \sqrt{\frac{m}{E}}\)
- D \(\sqrt{\frac{E d}{m}}\)
Answer & Solution
Correct Answer
(A) \(\frac{2}{d} \sqrt{\frac{E}{m}}\)
Step-by-step Solution
Detailed explanation
\(I = 2m \left(\frac{d}{2}\right)^2 = \frac{1}{2}md^2\) \(E = \frac{1}{2}I\omega^2\)
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