MHT CET · Physics · Current Electricity
A milliammeter of resistance \(40 \Omega\) has a range \(0-30 \mathrm{~mA}\). What will be the resistance
used in series to convert it into voltmeter of range \(0-15 \mathrm{~V}\) ?
- A \(640 \Omega\)
- B \(920 \Omega\)
- C \(560 \Omega\)
- D \(460 \Omega\)
Answer & Solution
Correct Answer
(D) \(460 \Omega\)
Step-by-step Solution
Detailed explanation
(A)
\(\begin{aligned} R &=\frac{V}{I_{g}}-G=\frac{15}{30 \times 10^{-3}}-40 \\ &=500-40=460 \Omega \end{aligned}\)
\(\begin{aligned} R &=\frac{V}{I_{g}}-G=\frac{15}{30 \times 10^{-3}}-40 \\ &=500-40=460 \Omega \end{aligned}\)
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