MHT CET · Physics · Electromagnetic Induction
A metal wire of length \(2500 \mathrm{~m}\) is kept in east-west direction, at a certain height from the ground. If it falls freely on the ground, then the current induced in the wire when its speed is \(10 \mathrm{~m} / \mathrm{s}\) is (Resistance of wire \(=25 \Omega, g=10 \mathrm{~m} / \mathrm{s}^2\) and Earth's horizontal component of magnetic field \(\mathrm{B}_{\mathrm{H}}=2 \times 10^{-5} \mathrm{~T}\) )
- A \(0.2 \mathrm{~A}\)
- B \(0.02 \mathrm{~A}\)
- C \(0.01 \mathrm{~A}\)
- D \(2 \mathrm{~A}\)
Answer & Solution
Correct Answer
(B) \(0.02 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Emf induced, e \(=\mathrm{B}_{\mathrm{H}} l\)
\(
\begin{aligned}
& =2 \times 10^{-5} \times 10 \times 2500=0.5 \mathrm{~V} \\
& \mathrm{I}=\mathrm{e} / \mathrm{R}=0.5 / 25=0.02 \mathrm{~A}
\end{aligned}
\)
\(
\begin{aligned}
& =2 \times 10^{-5} \times 10 \times 2500=0.5 \mathrm{~V} \\
& \mathrm{I}=\mathrm{e} / \mathrm{R}=0.5 / 25=0.02 \mathrm{~A}
\end{aligned}
\)
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