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MHT CET · Physics · Mechanical Properties of Solids

A metal sphere of radius \(1 \mathrm{~m}\) is charged with \(10^{-2} \mathrm{C}\) in air. Its bulk modulus is
\(10^{11} / 4 \pi^{2}\). The volume strain in the sphere is \(\left(\epsilon_{0}=\right.\) pemittivity of free space)

  1. A \(\frac{10^{-1}}{6 \in_{0}}\)
  2. B \(\frac{10^{-14}}{8 \epsilon_{0}}\)
  3. C \(\frac{10^{-15}}{8 \epsilon_{0}}\)
  4. D \(\frac{10^{-12}}{4 \in_{0}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{10^{-15}}{8 \epsilon_{0}}\)

Step-by-step Solution

Detailed explanation

surface charge density
\(\sigma=\frac{q}{4 \pi r^{2}}=\frac{10^{-2}}{4 \pi \times 1}=\frac{10^{-2}}{4 \pi} \mathrm{C} / \mathrm{m}^{2}\)
strain \(=\)
\(\frac{F}{A}=\frac{1}{2} \frac{\sigma^{2}}{\varepsilon_{2}}=\frac{1}{2 \varepsilon_{0}} \times\left(\frac{10^{-2}}{4 \pi}\right)^{2}=\frac{10^{-4}}{32 \pi^{2} \varepsilon_{0}}\)
strain \(=\frac{\text { stress }}{k}=\frac{1}{2} \frac{\sigma^{2}}{\varepsilon_{0} k}\)
where \(k=\frac{10^{11}}{4 \pi^{2}}\)
substituting and calculating we get strain =
\(\frac{10^{-15}}{8 \varepsilon_{0}}\)
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