MHT CET · Physics · Thermal Properties of Matter
A metal rod of cross-sectional area \(3 \times 10^{-6} \mathrm{~m}^{2}\) is suspended vertically from one
end has a length \(0 \cdot 4 \mathrm{~m}\) at \(100^{\circ} \mathrm{C}\). Now the rod is cooled upto \(0^{\circ} \mathrm{C}\), but prevented
from contracting by attaching a mass ' \(\mathrm{m}\) ' at the lower end. The value of ' \(\mathrm{m}\) ' is
\(\left(\mathrm{Y}=10^{11} \mathrm{~N} / \mathrm{m}^{2}\right.\), coefficient of linear expansion \(\left.=10^{-5} / \mathrm{K}, \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
- A \(40 \mathrm{~kg}\)
- B \(20 \mathrm{~kg}\)
- C \(30 \mathrm{~kg}\)
- D \(10 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(C) \(30 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{L}=\mathrm{L} \propto \Delta \mathrm{T}=\frac{\mathrm{FL}}{\mathrm{AY}}\)
\(\therefore \mathrm{F}=\mathrm{AY} \propto \Delta \mathrm{T}\)
\(\therefore \mathrm{Mg}=\mathrm{AY} \propto \Delta \mathrm{T}\)
\(\mathrm{M}=\frac{\mathrm{AY} \propto \Delta \mathrm{T}}{\mathrm{g}}=\frac{3 \times 10^{-6} \times 10^{11} \times 10^{-5} \times 100}{10}=30 \mathrm{~kg}\)
\(\therefore \mathrm{F}=\mathrm{AY} \propto \Delta \mathrm{T}\)
\(\therefore \mathrm{Mg}=\mathrm{AY} \propto \Delta \mathrm{T}\)
\(\mathrm{M}=\frac{\mathrm{AY} \propto \Delta \mathrm{T}}{\mathrm{g}}=\frac{3 \times 10^{-6} \times 10^{11} \times 10^{-5} \times 100}{10}=30 \mathrm{~kg}\)
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