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MHT CET · Physics · Thermal Properties of Matter

A metal rod \(2 \mathrm{~m}\) long increases in length by \(1.6 \mathrm{~mm}\), when heated from \(0^{\circ} \mathrm{C}\) to \(60^{\circ} \mathrm{C}\). The coefficient of linear expansion of metal rod is

  1. A \(1.33 \times 10^{-5} /{ }^{\circ} \mathrm{C}\)
  2. B \(1.66 \times 10^{-5} /{ }^{\circ} \mathrm{C}\)
  3. C \(1.33 \times 10^{-3} /{ }^{\circ} \mathrm{C}\)
  4. D \(1.66 \times 10^{-3} /{ }^{\circ} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1.33 \times 10^{-5} /{ }^{\circ} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

We know,
Coefficient of Linear expansion \(\alpha=\frac{\mathrm{L}_2-\mathrm{L}_1}{\mathrm{~L}_1 \Delta \mathrm{T}}... (i)\)
Given: \(\Delta \mathrm{T}=60-0=60^{\circ} \mathrm{C}\)
\(\mathrm{L}_1=2 \mathrm{~m}\) and \(\mathrm{L}_2=2.0016\)
Substituting the given values into (i),
\(\alpha=\frac{.0016}{120}=1.33 \times 10^{-5} /{ }^{\circ} \mathrm{C}\)
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