MHT CET · Physics · Oscillations
A mass suspended from a vertical spring performs S.H.M. of period \(0 \cdot 1\) second. The spring is unstretched at the highest point of suspension. Maxmimum speed of the mass is (Gravitational acceleration \(\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)\)
- A \(\frac{1}{2 \pi} \mathrm{~m} / \mathrm{s}\)
- B \(\frac{1}{\pi} \mathrm{~m} / \mathrm{s}\)
- C \(\frac{2}{\pi} \mathrm{~m} / \mathrm{s}\)
- D \(\pi \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{2 \pi} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(A = \frac{g T^2}{4\pi^2}\) \(v_{max} = A\omega = \frac{g T^2}{4\pi^2} \cdot \frac{2\pi}{T}\)
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