MHT CET · Physics · Oscillations
A mass 'M' attached to a horizontal spring executes S.H.M. of amplitude \(A_1\). When the mass \(M\) passes through its mean position, then a smaller mass ' m ' is placed over it and both of them move together with amplitude \(A_2\). The ratio \(\left(\frac{A_1}{A_2}\right)\) is
- A \(\frac{M+m}{M}\)
- B \(\frac{M}{M+m}\)
- C \(\left(\frac{M+m}{M}\right)^{\frac{1}{2}}\)
- D \(\left(\frac{M}{M+m}\right)^{\frac{1}{2}}\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{M+m}{M}\right)^{\frac{1}{2}}\)
Step-by-step Solution
Detailed explanation
\(M v_1 = (M+m) v_2\) \(M (A_1 \sqrt{\frac{k}{M}}) = (M+m) (A_2 \sqrt{\frac{k}{M+m}})\)
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