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MHT CET · Physics · Magnetic Properties of Matter

A magnetic intensity of \(500 \mathrm{~A} / \mathrm{m}\), produces a magnetic flux of \(2.4 \times 10^{-5} . \mathrm{Wb}\) in an iron bar of cross-sectional area \(0.4 \mathrm{~cm}^2\). The magnetic permeability of the iron bar is

  1. A \(2.4 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2\)
  2. B \(1.2 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2\)
  3. C \(2.4 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2\)
  4. D \(1.2 \times 10^{-4} \mathrm{~N} / \mathrm{m}^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1.2 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2\)

Step-by-step Solution

Detailed explanation

Permeability of iron bar,
\(\mu=\frac{B}{H}=\frac{(\phi / \mathrm{A})}{\mathrm{H}}=\frac{\phi}{\mathrm{HA}}=\frac{2.4 \times 10^{-5}}{500 \times\left(0.4 \times 10^{-4}\right)}\)
\(\therefore \mu =1.2 \times 10^{-3} \mathrm{~N} / \mathrm{m}^2\)
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