MHT CET · Physics · Electromagnetic Induction
A long rectangular conducting loop of width ' \(\ell\) ', mass ' m ' and resistance ' R ' is placed partly in a perpendicular magnetic field ' B '. It is pushed downwards with velocity ' \(V\) ' so that it may continue to fall freely. The velocity ' \(V\) ' is
- A \(\frac{\mathrm{mg} \mathrm{R}^2}{\mathrm{~B} \ell}\)
- B \(\frac{\mathrm{B}^2 \ell^2 \mathrm{R}}{\mathrm{mg}}\)
- C \(\frac{\mathrm{mg} \mathrm{R}}{\mathrm{B}^2 \ell^2}\)
- D \(\frac{\mathrm{mg} \ell}{\mathrm{B}^2 \mathrm{R}^2}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{mg} \mathrm{R}}{\mathrm{B}^2 \ell^2}\)
Step-by-step Solution
Detailed explanation
\(F_{magnetic} = F_{gravity}\) \(I \ell B = mg\)
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