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MHT CET · Physics · Mechanical Properties of Fluids

A liquid drop having surface energy E is spread into 512 droplets of the same size. The final surface energy of the droplets is

  1. A 2E
  2. B 4E
  3. C 8E
  4. D 12E
Verified Solution

Answer & Solution

Correct Answer

(C) 8E

Step-by-step Solution

Detailed explanation

The surface area of the liquid drop is A=4πR2
Its surface energy is E
When the drop splits in 512 droplets, the surface area of each droplet is 4πr2
Total surface area A2 =512×4πr2
The volume of the bigger drop is 43πR3 and the volume of small droplets is 512×43πr3
  43πR3=512×43πr3r=R8
  A2=512×4πr2=512×4πR82=8A1
Surface energy E=A.T (T is surface tension and A is area)
  EnE0=A2TA1T=8A1A1=8
 En=8E
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