MHT CET · Physics · Wave Optics
A light wave of wavelength \(\lambda^{\prime}\) is incident on a slit of width 'd'. The resulting diffraction pattern is observed on a screen at a distance 'D'. If linear width of the principal maxima is equal to the width of the slit, then the distance 'D' is
- A \(\frac{\mathrm{a}}{\lambda}\)
- B \(\frac{2 \lambda}{\mathrm{d}}\)
- C \(\frac{\mathrm{d}^{2}}{2 \lambda}\)
- D \(\frac{2 \lambda^{2}}{\mathrm{~d}}\)
Answer & Solution
Correct Answer
(C) \(\frac{\mathrm{d}^{2}}{2 \lambda}\)
Step-by-step Solution
Detailed explanation
(D)
\(\begin{array}{l}
\beta=\frac{2 \lambda D}{d}=d \\
\therefore D=\frac{d^{2}}{2 \lambda}
\end{array}\)
\(\begin{array}{l}
\beta=\frac{2 \lambda D}{d}=d \\
\therefore D=\frac{d^{2}}{2 \lambda}
\end{array}\)
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