MHT CET · Physics · Ray Optics
A light travels through water in the beaker. The height of water column is 'h'.
Refractive index of water is ' \(\mu_{\mathrm{w}}^{\prime}\). If \(\mathrm{C}\) is velocity of light in air, the time taken by
light to travel through water will be
- A \(\frac{\mu_{\mathrm{w}} \mathrm{h}}{\mathrm{C}}\)
- B \(\mathrm{h} \mu_{\mathrm{w}} \mathrm{C}\)
- C \(\frac{\mathrm{hC}}{\mu_{\mathrm{w}}}\)
- D \(\frac{\mathrm{h}}{\mu_{\mathrm{w}} \mathrm{C}}\)
Answer & Solution
Correct Answer
(A) \(\frac{\mu_{\mathrm{w}} \mathrm{h}}{\mathrm{C}}\)
Step-by-step Solution
Detailed explanation
Velocity \(=\frac{\text { distance }}{\text { time }}\)
\(\therefore\) time \(=\frac{\text { distance }}{\text { velocity }}=\frac{\mathrm{h}}{\mathrm{c}} \mu_{\mathrm{w}}\)
\(\therefore \mu_{\mathrm{w}}=\frac{\mathrm{c}}{\mathrm{v}} \quad \therefore \mathrm{v}=\frac{\mathrm{c}}{\mu_{\mathrm{w}}}\)
\(\therefore\) time \(=\frac{\text { distance }}{\text { velocity }}=\frac{\mathrm{h}}{\mathrm{c}} \mu_{\mathrm{w}}\)
\(\therefore \mu_{\mathrm{w}}=\frac{\mathrm{c}}{\mathrm{v}} \quad \therefore \mathrm{v}=\frac{\mathrm{c}}{\mu_{\mathrm{w}}}\)
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