MHT CET · Physics · Dual Nature of Matter
A light of wavelength \(\lambda\) is incident on a photosensitive surface of negligible work function. The photoelectrons emitted from the surface have de-Broglie wavelength \(\lambda_1\). Then ratio \(\lambda: \lambda_1^2\) is ( \(\mathrm{h}=\) Planck's constant, \(\mathrm{c}=\) velocity of light, \(\mathrm{m}=\) mass of electron)
- A \(4 \mathrm{mc}: \mathrm{h}\)
- B \(2 c: h\)
- C \(2 \mathrm{mc}: \mathrm{h}\)
- D \(2 \mathrm{mh}: \mathrm{c}\)
Answer & Solution
Correct Answer
(C) \(2 \mathrm{mc}: \mathrm{h}\)
Step-by-step Solution
Detailed explanation
\(\frac{hc}{\lambda} = \frac{p^2}{2m} = \frac{(h/\lambda_1)^2}{2m} = \frac{h^2}{2m\lambda_1^2}\) \(\frac{\lambda}{\lambda_1^2} = \frac{hc \cdot 2m}{h^2} = \frac{2mc}{h}\)
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