MHT CET · Physics · Dual Nature of Matter
A light of wavelength ' \(\lambda\) ' and intensity ' \(I\) ' falls on photosensitive material. If ' \(\mathrm{N}\) ' photo electrons are emitted, each with kinetic energy ' \(E\) ', then
- A \(E \propto I, N \propto \lambda\)
- B \(\mathrm{E} \propto \mathrm{I}, \mathrm{N} \propto \mathrm{I}\)
- C \(\mathrm{E} \propto \mathrm{I}, \mathrm{N} \propto \frac{1}{\lambda}\)
- D \(\mathrm{E} \propto \frac{1}{\lambda}, \mathrm{N} \propto \mathrm{I}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{E} \propto \frac{1}{\lambda}, \mathrm{N} \propto \mathrm{I}\)
Step-by-step Solution
Detailed explanation
Intensity is proportional to the number of photons, since each photon interacts with one electron, the number of electron \(\mathrm{N} \propto \mathrm{I}\). Energy of photon is \(\frac{h c}{\lambda}\), hence it is inversely proportional to the wavelength.
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