MHT CET · Physics · Center of Mass Momentum and Collision
A large number of bullets are fired in all directions with same speed ' \(U\) '. The maximum area on the ground on which the bullets will spread is
- A \(\frac{\pi \mathrm{u}^2}{\mathrm{~g}}\)
- B \(\frac{\pi \mathrm{u}^4}{\mathrm{~g}^2}\)
- C \(\frac{\pi^2 u^4}{g^2}\)
- D \(\frac{\pi^2 u^2}{g^2}\)
Answer & Solution
Correct Answer
(B) \(\frac{\pi \mathrm{u}^4}{\mathrm{~g}^2}\)
Step-by-step Solution
Detailed explanation
Area in which bullet will spread \(=\pi r^2\) For maximum area, \(r=R_{\max }=\frac{\mathrm{u}^2}{\mathrm{~g}}\left[\right.\) when \(\left.\theta=45^{\circ}\right]\) Maximum area \(\pi \mathrm{R}_{\max }^2=\pi\left(\frac{\mathrm{u}^2}{\mathrm{~g}}\right)^2=\frac{\pi \mathrm{u}^4}{\mathrm{~g}^2}\)
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